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BartSMP [9]
3 years ago
15

Express the sum in the simplest form 3x/x+5 + 7/x+5

Mathematics
2 answers:
disa [49]3 years ago
8 0
(3x+7) / (x+5). ....................
nasty-shy [4]3 years ago
8 0
<h2>Answer:</h2>

The sum of the given expression in simplest form is:

          \dfrac{3x+7}{x+5}

<h2>Step-by-step explanation:</h2>

We are asked to sum up two rational function.

The first rational function is:

\dfrac{3x}{x+5}

and the other i.e. second rational function is given by:

\dfrac{7}{x+5}

Now, on adding these two i.e.

\dfrac{3x}{x+5}+\dfrac{7}{x+5}

Since both the terms have the same denominator.

Hence, the denominator is taken as one and the quantities in the numerator are added up.

Hence, the expression is given by:

\dfrac{3x}{x+5}+\dfrac{7}{x+5}=\dfrac{3x+7}{x+5}

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1) What can u do to get 2x alone on the left side?
CaHeK987 [17]

Answer:

1)

82.5 - <u>8</u><u>2</u><u>.</u><u>5</u> + 2x = 338.5 - <u>8</u><u>2</u><u>.</u><u>5</u>

<u>2</u>x = <u>2</u><u>5</u><u>6</u>

2)

2x ÷ <u>2</u> = 256 ÷ <u>2</u>

x = <u>1</u><u>2</u><u>8</u>

Step-by-step explanation:

1)

In order to get rid 82.5, you have to substract the same value on both side to get a 0 value.

2)

In order to find the value of x, you have to divide the value that is sticked with x which is 2. As you divide 2 by 2, you will get 1 as a single value of x so you have to divide 2 to both side too.

5 0
3 years ago
Me need more help plz also add explanation real explanation
Reika [66]

So we want to find the surface area of this pyramid. Finding the surface area of a 3D shape is essentially finding the area of all its sides and adding them together.

What we're going to have to do here is find the area of the base of the pyramid, which is basically a square, and find the area of all four sides of the pyramid, which are triangles.

Formula for area of a square: length × width

Formula for area of a triangle: (base × height) ÷ 2

First we will find the area of the base:

l × w = A

(Write out formula)

8 × 8 =

(Input values)

A = 64 m^2 (square meters or meters squared)

(We have our answer, dont forgot to write your units.)

So we've figured out the area of the base. Now onto the triangles:

(b×h) ÷ 2 = A

(Write out formula)

(8 × 6) ÷ 2 =

(Input values)

48 ÷ 2 =

(Use PEMDAS to solve this correctly. We did whatever was in the parenthesis first, which was multiplication.)

A = 24m^2 (square meters or meters squared)

(We have our answer.)

Now we've found the area of the base of the pyramid and one of the sides of the pyramid, but we're almost done! There's four sides to the pyramid, they're all the same. So since we found the area for one, we can multiply that by 4 to find the area of all sides added together:

24 × 4

(area of a side × total sides)

= 96m^2

All that's left is adding the 96 to the area of the base to get our total surface area of the pyramid:

96 + 64 = 160

The surface area of the pyramid is 160m^2(square meters or meters squared)

(Hope this helps :) )

8 0
2 years ago
Read 2 more answers
What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po
emmasim [6.3K]
\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS
\displaystyle\iint_\sigma\mathbf F\cdot\mathbf n\,\mathrm dS
\displaystyle\iint_\sigma\mathbf F\cdot\left(\frac{\mathbf r_u\times\mathbf r_v}{\|\mathbf r_u\times\mathbf r_v\|}\right)\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dA
\displaystyle\iint_\sigma\mathbf F\cdot(\mathbf r_u\times\mathbf r_v)\,\mathrm dA

Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k
\mathbf r_v=\dfrac\partial{\partial v}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=-2\sin v\,\mathbf i+\cos v\,\mathbf j

The cross product is

\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j

So, the flux is given by

\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA
\displaystyle\int_0^5\int_0^{2\pi}(-e^{-\sin v}\cos v+2\sin^2v)\,\mathrm dv\,\mathrm du
\displaystyle-5\int_0^{2\pi}e^{-\sin v}\cos v\,\mathrm dv+10\int_0^{2\pi}\sin^2v\,\mathrm dv
\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv

where t=-\sin v in the first integral, and the half-angle identity is used in the second. The first integral vanishes, leaving you with

\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi
5 0
3 years ago
What are two numbers that have a product of 15 but also a sum of 8
Kruka [31]

Answer:

3 and 5

Step-by-step explanation:

3+5=8, and also

3x5=15

5 0
3 years ago
Mr. Toshi's fifth grade class sold
kozerog [31]

Answer:

775

Step-by-step explanation:

If each day you subtract 25 you will get 200,175,125,275.. if you add them all together you'd get 775.

3 0
3 years ago
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