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Juli2301 [7.4K]
3 years ago
8

There are 163 adults and 37 students in the audience. Will 4 packages of 50 programs be enough for each person in the audience t

o receive a program? explain
Mathematics
2 answers:
nata0808 [166]3 years ago
4 0

there are 200 people in total in the audience, assuming that each person receives only one program, 4 packages of 50 programs will be enough because 50 x 4 = 200 and 163+37= 200 and if each person gets 1 program, there are enough programs.

Illusion [34]3 years ago
3 0

163+ 37 = 200 people

4* 50 = 200 programs

There will be exactly enough programs for every person to get one

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A garden hose having an internal diameter of 0.740 in. ( 1.8796 cm ) is connected to a lawn sprinkler that consists merely of an
lara31 [8.8K]

Answer:

It will leave the sprinkler at speed of v_2=613.87m/sec

Step-by-step explanation:

We have given internal diameter of the garden hose d_1=0.740in=1.8796cm

So radius r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm

So area A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2

Water in the hose has a speed of 4 ft/sec

So v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)

Number of holes n = 36

Diameter of each hole d_2=0.1397cm

So radius r_2=0.0698cm

So area A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2

From continuity equation

A_1v_1=nA_2v_2

2.7733\times 121.92=36\times 0.0153\times v_2

v_2=613.87m/sec

7 0
3 years ago
What is the missing number?
JulsSmile [24]

Answer:

y = 2^{x}

Step-by-step explanation:

Given the above data for x and y.

From the algebraic expression;

y = 2^{x}

We can deduce that the value of y is equal to two (2) raise to the power of x.

When x = 1, y = 2

y = 2^{x}

y = 2^{1}

y = 2

When x = 2, y = 4

y = 2^{x}

y = 2^{2}

y = 4

When x = 3, y = 8

y = 2^{x}

y = 2^{3}

y = 8

The above calculations can be used to determine the other values of y with respect to x.

3 0
3 years ago
Which place is home of the first known written code of law?
lesya692 [45]
The answer should be B. Mesopotamia
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5 0
3 years ago
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Find the area of a rectangle that is 7 cm long and 3 cm wide. You can use the tool to help you solve. 7 cm2 10 cm2 20 cm2 21 cm2
stiks02 [169]

Answer:

21sq

Step-by-step explanation:

multiply the l times the w which would be 3x7 and get 21.

8 0
3 years ago
Describe each of the following transformation that maps the figures described below. Be specific by naming lines of reflection,
Flura [38]

Answer:

Part A: Figure 1 → Figure 4

Rigid Transformation

Equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin which are types of rigid transformation

Part B: Figure 2 → Figure 5

Similarity transformation

Figure 5 is Figure 2 dilated by a scale factor of 1/2, which is a form of a similarity transformation

Step-by-step explanation:

Part A: Figure 1 → Figure 4

The coordinates of the vertices of the preimage are;

(5, 10), (2, 4), (9, 2)

The coordinates of the vertices of the image are;

(-9, -2), (-2, -4), (-5, -10)

Which is equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin

Part B: Figure 2 → Figure 5

The coordinate points of figure 2 are;

(-9, 2), (-5, 10), and (-2, 4)

The coordinate points of figure 5 are;

(1, 2), (2.5, -1), and (4.5, 3)

The lengths of the sides of figure 2 are;

√((10 - 2)² + ((-5) - (-9))²) = 4·√5

√((10 - 4)² + ((-5) - (-2))²) = 3·√5

√((2 - 4)² + ((-9) - (-2))²) = √53

The lengths of the sides of figure 5 are;

√(((-1) - 2)² + (2.5 - 1)²) = (3·√5)/2

√((4.5 - 2.5)² + (3 - (-1))²) = 2·√5

√((4.5 - 1)² + (3 - 2)²) = (√53)/2

Therefore. Figure 5 is Figure 2 dilated by a scale factor of 1/2

Therefore, given that the sides of Figure 2 and Figure 5 are rotated by 180°

We have;

Figure 5 is obtained as follows;

1) The rotation of figure 2 by 180°, clockwise or anticlockwise about the origin to get;

(-9, 2), (-5, 10), and (-2, 4) → (9, -2), (5, -10), and (2, -4)

2) The image is translated left by 1 blocks and up by 6 blocks as follows;

(9, -2), (5, -10), and (2, -4)  → (8, 4), (4, -4), and (1, 2)

3) The image is then dilated by a scale factor of 1/2  with a center of dilation of (1, 2) to get;

Preimage (8, 4), (4, -4), and (1, 2) → Image (1, 2), (2.5, -1), and (4.5, 3).

8 0
3 years ago
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