Solve for x, please thanks
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The area of figure ABCDEF can be computed as the sum of the areas of trapezoid ACDF and triangle ABC, less the area of trangle DEF.
trapezoid ACDF area = (1/2)(AC +DF)·(CD) = (1/2)(8+5)(6) = 39
triangle ABC area = (1/2)(AC)(2) = 8
triangle DEF area = (1/2)(DF)(2) = 5
Area of ABCDEF = (ACDF area) + (ABC area) - (DEF area) = 39 +8 -5 = 42
The actual area of ABCDEF is 42 square units.
trapezoid ACDF area = (1/2)(AC +DF)·(CD) = (1/2)(8+5)(6) = 39
triangle ABC area = (1/2)(AC)(2) = 8
triangle DEF area = (1/2)(DF)(2) = 5
Area of ABCDEF = (ACDF area) + (ABC area) - (DEF area) = 39 +8 -5 = 42
The actual area of ABCDEF is 42 square units.