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aniked [119]
3 years ago
9

Which complex number does NOT fall within the shaded region in this graph?

Mathematics
1 answer:
avanturin [10]3 years ago
4 0
In order to find which is the answer, we will go step-by-step. Numbers that are not followed by I are drawn on the Real Axis and the other ones are drawn on the Imaginary Axis. You go first on the Real Axis and then on the Imaginary Axis and intersect those 2 points. If a number does not have an imaginary or real part you can assume that is equal to 0. As you can notice the number that is not in the shaded area is <span>2 − I</span>
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If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] ^2.
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Someone please help me on this I have 5 minutes!
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Sam has ⅙ of a book left to read. He wants to finish the book by reading the same amount every day for 4 days. How much of the b
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4. A safe slope for a ladder is 1 ft of run for every 4 ft of rise. Vincent needs to use a
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5.5 ft

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Consider the probability that greater than 96 out of 153 DVDs will work correctly. Assume the probability that a given DVD will
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Answer:

0.3594 = 35.94% probability that greater than 96 out of 153 DVDs will work correctly.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 153, p = 0.62

So

\mu = E(X) = np = 153*0.62 = 94.86

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.62*0.38} = 6

Probability that greater than 96 out of 153 DVDs will work correctly.

97 or more DVDs, which is 1 subtracted by the pvalue of Z when X = 97. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{97 - 94.86}{6}

Z = 0.36

Z = 0.36 has a pvalue of 0.6406

1 - 0.6406 = 0.3594

0.3594 = 35.94% probability that greater than 96 out of 153 DVDs will work correctly.

3 0
3 years ago
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