How many triangles can be constructed with angles measuring 10º, 80º, and 90º?

Mathematics

1 answer:

Svet_ta [14]2 years ago

5 0

Answer:There are 180 degrees in one triangle

Step-by-step explanation:more than one because lengths were not given for any side

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How many 5-digit numbers can be formed from the integers 1, 2, ... , 9 if no digit can appear more than twice?

elena-14-01-66 [18.8K]

5 digit number with no repeats
1st digit has 9 possibilities
2nd digit has 8 possibilities
3rd digit has 7 possibilities
4th digit has 6 possibilities
5th fight has 5 possibilities
Therefore the answer is:
9 x 8 x 7 x 6 x 5 = 72 x 210 = 15,120

6 0

3 years ago

Find the volume of the cone.

frutty [35]

Answer:5

Step-by-step explanation:

Because

7 0

3 years ago

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle L = \sqrt{4kt - p}$

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, add p to both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, divide 4t by both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$