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oee [108]
3 years ago
9

Combine like terms: 3p2q2-3p2q3+4p2q3-3p2q2+pq PLEASE HELP!!! ASAP!!!

Mathematics
1 answer:
ch4aika [34]3 years ago
7 0

Answer:

p²q³ + pq and pq(pq² + 1)

Step-by-step explanation:

Given

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Required

Collect like terms

We start by rewriting the expression

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Collect like terms

3p²q² -3p²q² - 3p²q³ +4p²q³ + pq

Group like terms

(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq

Perform arithmetic operations on like terms

(0) - (-p²q³) + pq

- (-p²q³) + pq

Open bracket

p²q³ + pq

The answer can be further simplified

Factorize p²q³ + pq

pq(pq² + 1)

Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)

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If the Volume of a box is 250 feet3 and the height is 5 feet and the length is 5
Montano1993 [528]

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Step-by-step explanation:

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2 years ago
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I am going to show you how easy this is. Once you understand, you will be able to do this forever.

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Assuming the side of the rectangle are (L) length and (W) width, the perimeter:

2L + 2W = 234

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"the rectangle is twice as long as it is wide,", the equation for this statement:

L = 2W

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In the first equation, we can replace L with 2W, then we have

2(2W) + 2W = 234

4W + 2W = 234

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Divide both sides by 6

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Remember it said the length is twice the width, therefore:

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Check this by finding the perimeter with these values

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