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Andrei [34K]
3 years ago
10

Is the answer a, b, c, or d.

Mathematics
2 answers:
Mars2501 [29]3 years ago
8 0
Your answer is C, comment if you would like me to send you the work for it 
kobusy [5.1K]3 years ago
7 0
For this case we have the following system of equations:
 x - 4y = 1
 x + 2y = 19
 Using the elimination method we have:
 -4y - 2y = 1 - 19
 -6y = -18
 y = -18 / -6
 y = 3
 Then, by clearing x from any equation we have:
 x + 2y = 19
 x = 19 - 2y
 x = 19 - 2 (3)
 x = 19 - 6
 x = 13
 The solution is given by:
 (x, y) = (13, 3)
 Answer:
 
x = 13
 
option c.
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Anastasy [175]

Answer:

range = {11,-1,-4,-13}

Step-by-step explanation:

domain is "input" range is "output"

just "plug" {-3, 1, 2,5} into -3x + 2 one at a time

5 0
3 years ago
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V125BC [204]

Answer:

In ∆ABC AND ∆DEF

ABC=DEF...........each 90°

SIDE AB =SIDE ED...........given

SIDE BC =SIDE EF............B-F-C and E-C-F

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3 0
3 years ago
Explain two different ways to find the difference for 12-3?
bulgar [2K]
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4 0
3 years ago
Solve the inequality for <br> 8w-35&lt; 3−(5-4w)<br><br> Simplify the answer as much as possible
Finger [1]

Answer:

w<33/4

Step-by-step explanation:

8w-35<3-(5-4w)

8w-35<3-5+4w

8w-35<-2+4w

8w-4w-35<-2

4w-35<-2

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7 0
3 years ago
A dog breeder would like to know how many Dalmatian puppies are typically born in a litter. He conducts some research and select
podryga [215]

Answer:

c. 6.2 ± 2.626(0.21)

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 101 - 1 = 100

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.626

The confidence interval is:

\overline{x} \pm M

In which \overline{x} is the sample mean while M is the margin of error.

The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.

This means that \overline{x} = 6.2

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.626\frac{2.1}{\sqrt{101}} = 2.626(0.21)

In which s is the standard deviation of the sample and n is the size of the sample.

Thus, the confidence interval is:

\overline{x} \pm M = 6.2 \pm 2.626(0.21)

And the correct answer is given by option c.

5 0
3 years ago
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