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agasfer [191]
3 years ago
9

If each side of a regular pentagon equals 4 feet , what is its permiter

Mathematics
2 answers:
kirill [66]3 years ago
7 0
4 feet x 5 = 20 feet
Tanya [424]3 years ago
4 0
The awnser is 20 feet
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2. Kiara baked 30 oatmeal cookies and 48 chocolate chip cookies to package in plastic containers for her friends at school. She
kolezko [41]

Answer:

you find the gcf/ greatest common factor of both numbers which is 6, so 6 plastic containers

Step-by-step explanation:

4 0
3 years ago
If f(x) = 4x - 7, what's the value of f(2) ? *<br> O -1<br> O 1<br> O 20<br> O 35
sp2606 [1]

Answer:

B

Step-by-step explanation:

f(x) = 4x - 7

What does f(x) mean? It means that whatever variable you have on the left which is (x), the same variable must be on the right.

So f(2) means that whatever variable is on the right, it must be replaced with 2 on the right. So .....

f(2) = 4(2) - 7

f(2) = 8 - 7

f(2) = 1

3 0
2 years ago
Angle Q = 85° Determine angle O.
kkurt [141]

Answer:

∠O = 95°

Step-by-step explanation:

since ∠Q = 85°, arc NOP = 2(85°) = 170°

arc PQN = 360° - arc NOP

arc PQN = 360° - 170° = 190°

∠O = 1/2(arc PQN) = 1/2(190°) = 95°

4 0
3 years ago
Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
3 years ago
Evaluate the expression when x = 2, y = 5, and z = 4.
Stolb23 [73]

10y+x²

10(5)+(2)²

10(5)+4

50+4

54

Therefore, the expression has a value of 54.

5 0
3 years ago
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