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3 years ago

5/x - 9/y = 19/610/x + 6/y = 13/6

Mathematics

1 answer:

Lana71 [14]3 years ago

5 0

Step-by-step explanation:

there are equation 1 and equation

multiplied equation 1 by 2

10/x-18/y=38/6

this is equation3

then equation 2 minus equation 3

24/y= -25/6

y= -144/25

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X^2 + 6x +15=0 solve the equation using the quadratic formula

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3 years ago

Describe does Glide Reflection from the preimage triangle and black to the image triangle in red

AveGali [126]

Answer:

Step-by-step explanation:

Lets look at V which is at (2,-4).

We will also look at it's image V' which is at (-2,-1).

Let's go through the choices:

a. translation left 4 units and down 1 unit reflection x axis

Translating V left 4 and down 1 would give us (2-4,-4-1)

(-2,-5)

Reflecting that across the x-axis would give us

(-2,5).

So this is not (-2,-1) so let's move on...

b. translation left 2 units and up 2 units reflection line x=1

Translating V left 2 and up 2 gives us

(2-2,-4+2)

(0,-2)

Now reflecting this over x=1 gives us

(2,-2). ( Imagine this x=1 which is verical going right smack between points (0,-2) and (2,-2).)

We still did not reach our goal image.

c. translation left 2 units up and up 3 units reflection y axis

Starting at V(2,-4) and moving left 2 & up 3 gives (2-2,-4+3)=(0,-1).

Now reflecting this over the vertical axis, the y-axis, gives us (0,-1).

So we did not reach our (-2,-1) point yet.

d. translation left 2 units and 3 units reflection line x=-1.

Starting at (2,-4) then moving left 2 and up 3 gives us (2-2,-4+3)=(0,-1).

Now we are reflecting over x=-1 which means we want to choose a point on the side making x=-1 the middle. Thuis point on the other side of (0,-1) of x=-1 would be (-2,-1) which is the goal.

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3 years ago

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3 years ago

Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

Pepsi [2]

Answer:

Step-by-step explanation:

Two lines are perpendicular if the first line has a slope of $m$ and the second line has a slope of $\frac{1}{-m}$ .

With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:

$5x - 2y = -6$

$-2y = -5x - 6$

$y = \frac{5}{2}x + 3$

We now know that $m = \frac{5}{2}$ for the first line, which means that the slope of the second line is $m = \frac{-2}{5}$ . With this, we have the following equation for our new line:

$y = \frac{-2}{5}x + C$

where $C$ is the Y-intercept that we now need to determine with the coordinates given in the problem statement, $(5, -4)$ :

$y = \frac{-2}{5}x + C$

$(-4) = \frac{-2}{5}(5) + C$

$-4 = -2 + C$

$C = -2$

Finally, we can create our line:

$y = \frac{-2}{5}x - 2$

$5y = -2x - 10$

$2x + 5y = -10$

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4 years ago

Read 2 more answers

Given f(x)=cos c and g(x)=cot x, what are the domain and range of f(g(x))?

ololo11 [35]

Answer:

Alternative C is the correct answer

Step-by-step explanation:

The first step is to determine the composite function;

$f[g(x)]$

$f[g(x)]=cos[cot(x)]$

We then employ a graphing utility to determine the range and the domain of the new function.

The range is the set of y-values for which the function is defined. In this case it is;

$[-1,1]$

On the other hand, the domain refers to the set of the x-values for which the function is real and defined. In this case; it is the set of real numbers x except x does not equal npi for all integers n.

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3 years ago

5/x - 9/y = 19/610/x + 6/y = 13/6​

5/x - 9/y = 19/610/x + 6/y = 13/6