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Fed [463]
3 years ago
10

Chantal cut an apple into a equal slices. She ate 4 slices and had 4 slices left. Which equation models the problem?

Mathematics
1 answer:
Citrus2011 [14]3 years ago
8 0
So equal slices
total=x
she ate 4 slices from x so -4
x-4
she had 4 left
x-4=4
the equation would be x-4=4
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Since both C & D are parallel, angle 2 is a corresponding angle to the angle of 108 degrees, so angle 2 is also 108 degrees
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A line goes through the points. (3,-5) and (5,-1)
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9+10 equals 21

Step-by-step explanation:

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HURRY TImed Which of the following is equivalent to 3 1/3? A 1/27 B 1 C 3√3 D 1log33
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Step-by-step explanation:

3 1/3 is a mixed number, and is equivalent to 10/3.

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3 years ago
The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10
Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

N\sim Pois(0.2)

P(N=r)=\frac{e^{-np}(np)^r}{r!}

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}

P(N=0)=\frac{e^{-0.2}}{1}

P(N=0)=e^{-0.2}

P(N=0)=0.8187

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute r\geq 2 in formula,

P(N\geq 2)=1-P(N

P(N\geq 2)=1-[P(N=0)+P(N=1)]

P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]

P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]

P(N\geq 2)=1-[0.8187+0.1637]

P(N\geq 2)=1-0.9825

P(N\geq 2)=0.0175

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0
3 years ago
-3/5x+-7/10+1/2x=-56
Savatey [412]

Answer:

x=553

Step-by-step explanation:

\frac{-3}{5} x+\frac{-7}{10} +\frac{1}{2} x=-56

Combine like terms:

-\frac{1}{10} x =-\frac{553}{10}

Multiply both sides by -10:

x=553

8 0
1 year ago
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