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Kazeer [188]
2 years ago
5

Original price: $32 ;Markup: 12.5% ;what is Retail Price

Mathematics
2 answers:
Trava [24]2 years ago
6 0
12.5% = .125
32 x .125 = 4
32 + 4 = $36
DENIUS [597]2 years ago
3 0
The Total price is $36.
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What is the answer to -3x - 6 + (-1)?​
Free_Kalibri [48]

Answer:

-3x - 7 is the furthest it can be simplified

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2 years ago
24-4x=15-3x10-x has how many solutions
Igoryamba
Your answer will be -1
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3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
Verizon [17]
A) 0.9803; 0.4803
B) 32

We calculate the z-score for this problem by using the formula:

z=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}

Using our formula, we have:

z=\frac{3.00-2.65}{\frac{0.85}{\sqrt{25}}}=2.06

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.9803.

To find the probability it is between the mean and this, we subtract the probability associated with the mean (0.5) from this:
0.9803 - 0.5 = 0.4803.

To find B, we first find the z-score for this.  Using a z-table (http://www.z-table.com) we see that the closest z-score would be 2.33.  We then set up our equation as

2.33=\frac{3.00-2.65}{\frac{0.85}{\sqrt{n}}}=\frac{0.35}{\frac{0.85}{\sqrt{n}}}
\\
\\2.33=0.35\div \frac{0.85}{\sqrt{n}}=0.35\times \frac{\sqrt{n}}{0.85}

Multiplying both sides by 0.85 we have
2.33(0.85) = 0.35√n
1.9805 = 0.35√n

Divide both sides by 0.35:
1.9805/0.35 = √n

Square both sides:
(1.9805/0.35)² = n
32 ≈ n
8 0
2 years ago
Solve for z<br><br> Z - 4/9 - 1/3 = 5/9
Aleks04 [339]

Answer:

4/3

Step-by-step explanation:

<em>Z-</em><em>4</em><em>/</em><em>9</em><em>-</em><em>1</em><em>/</em><em>3</em><em>=</em><em>5</em><em>/</em><em>9</em>

<em>Z-</em><em>7</em><em>/</em><em>9</em><em>=</em><em>5</em><em>/</em><em>9</em>

<em>Z</em><em>=</em><em>5</em><em>/</em><em>9</em><em>+</em><em>7</em><em>/</em><em>9</em><em> </em>

<em>Z</em><em>=</em><em>4</em><em>/</em><em>3</em><em> </em><em>not</em><em> </em><em>sure</em><em> </em><em />

3 0
3 years ago
Avanety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each
AveGali [126]

Answer:

The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs

of crackers

Step-by-step explanation:

IQR of trail mix data = 105 - 90 = 15

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Therefore, the first option is NOT TRUE.

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The upper quartile of the trail mix data = 105.

The maximum value of the cracker data = 100.

Therefore, the third option is NOT TRUE.

Range can be used to determine how much variable there is in a data represented on a box plot. The greater the range value, the greater the variation.

Range of trail mix data = 115 - 70 = 45

Range of cracker data = 100 - 70 = 30.

<em>The range value for the number of calories in trail mix is greater than that for cracker, therefore, the number of calories in the packs of trail mix have a greater variation than the number of calories in the packs</em>

<em>of crackers.</em>

The fourth option is TRUE.

7 0
3 years ago
Read 2 more answers
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