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kondor19780726 [428]
3 years ago
11

Given that secant theta = Negative StartFraction 37 Over 12 EndFraction, what is the value of cotangent theta, for StartFraction

pi Over 2 EndFraction less-than theta less-than pi
Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0

cot\theta  =\frac{12}{35}

Step-by-step explanation:

sec\theta =\frac{37}{12}

⇔\frac{1}{cos \theta} =\frac{37}{12}

⇔cos \theta = \frac{12}{37}

we know that

sin \theta = \sqrt{1-cos^2\theta}

sin\theta =\sqrt{1-(\frac{12}{37})^2 }

sin\theta=\sqrt{\frac{1225}{1369} }

sin\theta = \frac{35}{37}

Therefore cot\theta =\frac{cos\theta}{sin\theta}  =\frac{\frac{12}{37} }{\frac{35}{37} }  =\frac{12}{35}  , for \frac{\pi}{2}

Kisachek [45]3 years ago
4 0

Answer:

i'm not sure but it might be -12/35

Step-by-step explanation:

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Solve the equation.<br> -2/3 (x + 3/5) = 1/2<br><br><br><br> x=
Rom4ik [11]
−
2
3
(
x
+
3
5
)
=
1
2
Step 1: Simplify both sides of the equation.
−
2
3
(
x
+
3
5
)
=
1
2
(
−
2
3
)
(
x
)
+
(
−
2
3
)
(
3
5
)
=
1
2
(Distribute)
−
2
3
x
+
−
2
5
=
1
2
Step 2: Add 2/5 to both sides.
−
2
3
x
+
−
2
5
+
2
5
=
1
2
+
2
5
−
2
3
x
=
9
10
Step 3: Multiply both sides by 3/(-2).
(
3
−
2
)
*
(
−
2
3
x
)
=
(
3
−
2
)
*
(
9
10
)
x
=
−
27
20
Answer:
x
=
−
27
20
6 0
2 years ago
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