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Veseljchak [2.6K]
3 years ago
12

ABC is a triangle. D is a point, vectors 2BD = 3DC Prove vectors 2AB + 3AC = 5AD

Mathematics
1 answer:
MakcuM [25]3 years ago
5 0

3Ac?????????????????

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The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f
fenix001 [56]

Answer:

Area of the figure = 31.25π cm²

Perimeter of the figure = (12.5π + 10) cm

Step-by-step explanation:

Area of the given figure = Sum of area of the two semicircle + area of a quarter circle

Area of one quarter circle (CDE) = \frac{1}{4}(\pi r^{2})

                                                      = \frac{1}{4}\pi (5)^2

                                                      = 6.25π

Area of one semicircle = 2 × Area of one quarter circle

                                      = 2(6.25π)

                                      = 12.5π

Area of the given figure = 2×12.5π + 6.25π

                                        = 25π + 6.25π

                                        = 31.25π cm²

Perimeter of the figure = Perimeter of two semicircles + perimeter of one quarter circle + measure of radius DE + measure of radius AB

Perimeter of one semicircle = πr

                                              = 5π cm

Perimeter of one quarter circle = 2.5π

Perimeter of the complete figure = 10π + 2.5π + 5 + 5

                                                       = (12.5π + 10) cm

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Answer:

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Step-by-step explanation:

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The y-value is increasing between x = -∞ and x = 0.

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The y-value is decreasing between x = 2 and x = +∞


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Step-by-step explanation:

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Step-by-step explanation:

Since 7+5 is 12 you got your first part. Now you have to find a thing that matches which is 1/9

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