ABC is a triangle. D is a point, vectors 2BD = 3DC Prove vectors 2AB + 3AC = 5AD
1 answer:
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The value is 333
<h3>How to determine the function</h3>From the information given, we have:
- x = - 8
- 1/3*h(x) = x^2-5x+7
Now, let's substitute the value of 'x' in the function:
1/3*h(x) = x^2-5x+7
1/ 3 × h(-8) = ( - 8)² - 5 ( -8) + 7
Make 'h ( -8)' the subject of formula
h ( -8) =
h ( -8) =
Take the sum of the numerator
h ( -8) =
Take the inverse of the denominator and multiply
h ( -8) = 111 × 3/ 1
h ( -8) = 333
We can see that through the substitute of the value of x as - 8, we get 333
Thus, the value is 333
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