Question

and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1

Answer 1

Answer:

$y\geq\frac{1}{3}x-1$

Step-by-step explanation:

A solid straight line has a positive slope and goes through (0, negative 1) and (3, 0)

Find the slope of the solid line

$m=(0+1)/(3-0)\\\\m=\frac{1}{3}$

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=\frac{1}{3}$

$b=-1$ ---> given problem

substitute

$y=\frac{1}{3}x-1$

Everything above and to the left of the line is shaded

so the inequality is equal to

$y\geq\frac{1}{3}x-1$

Answer 2

Answer:

Step-by-step explanation:

its B just took the quiz

y ≥ One-thirdx − 1