Both parents are normal. But, some of the kids have the disease. This indicates that the parents are heterozygous for the disease (let's use Dd). They are phenotypically fine because D is normal. But we know they must both carry the diseased d allele because their kids have the disease.
If you cross Dd x Dd you get DD, Dd, Dd and dd as the possible outcomes. But because each time they have a child they roll the dice as to which of the 4 above happens, they were unlucky as 3 of those times they got dd for their child...so 3 of them have the disease (and are dd). One is phenotypically normal but could still be Dd or DD.
Answer:
a virus, because it requires a host cell to reproduce
Explanation:
- a bacterium, because it is contagious
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a fungus, because it infects livestock
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a protist, because it is microscopic
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a virus, because it requires a host cell to reproduce
The correct answer would be <u>a virus because a virus is the only microbe that cannot reproduce on its own without a host</u>. A virus utilizes the genetic mechanism of its host to reproduce either lytically or lysogenically.
<u>In lytic cycle</u>, the virus utilizes the genome system of the host to produce more viruses that eventually leave or lyses the host to become independent viral particles, killing the host in the process.
<u>In lysogenic cycle</u>, the virus inserts its genome into that of the host and uses the host's replication machinery to replicate its genome. The virus then waits for the defense mechanism of the host to become weakened before multiplying and lysing the host.
Answer:
Glucose Transport
Explanation:
Glucose Transport is a highly regulated process accomplished mostly by facilitated diffusion using carrier proteins to cross cell membranes.
<em>Hope this helped! if so, please mark as brainliest!</em>
Answer:
i thin second one i thinl so it cirret
