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salantis [7]
3 years ago
12

71% of 67 how do i set it up

Mathematics
1 answer:
vodomira [7]3 years ago
5 0
67 × .71
61 \times .71
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Whoever gets this right gets brainlyess answer and it's worth 10 points :)
Artist 52 [7]
Area of ∆=1/2bh
80yd^2=1/2(b)(10yd)
80yd^2=5yd(b)
80yd^2÷5yd=b
16yd=b
8 0
2 years ago
Find the product.<br><br> a^4(3a ^2 - 2a + 1)
Vikki [24]

<span>                   a⁴(3a² - 2a + 1)

We just have to multiply each term inside the parentheses by  a⁴  .

           a⁴</span><span>(3a²        )  =  3a⁶
 
           a⁴</span><span>(    - 2a    )  =  -2a⁵
 
           a⁴</span><span>(            1)  =  a⁴

Now, just addum up :      3a⁶ - 2a⁵ + a⁴</span>


7 0
3 years ago
98 Points! MATH SOLVING SYSTEMS OF LINEAR EQUATIONS
photoshop1234 [79]

Answer:

40 Tickets

80 Tickets

Step-by-step explanation:

To find how many tickets it will take to break even, we use the formula:

Break Even In Units = \dfrac{FixedCost}{SalesPricePerUnit-VariableCost}

Our variables are:

Fixed Cost = $200

Sales Price = $10

Variable Cost = $5

Let's plug in our values into the formula.

Break Even In Units = \dfrac{200}{10-5}

Break Even In Units = \dfrac{200}{5}

Break Even In Units = 40

So the class needs to sell a total of 40 Tickets to break even.

Since we know that it takes 40 tickets to break even a $200 Fixed cost. To make a profit of $200, we simply multiply the number of tickets sold by 2.

Number of tickets for $200 profit = 40 x 2

Number of tickets for $200 profit = 80 Tickets.

So the class needs to sell 80 Tickets to make a $200 Profit.

5 0
2 years ago
The derivative of (x^2 +1)(x^3+ 1) (by definition and basic rule)
dlinn [17]

Answer:

f'(x) = 5x^4 + 2x + 3x^2

Step-by-step explanation:

To find the derivative of this equation we can do two things.

One method is to use the product rule, which states that when f(x) consists of two functions multiplied to each other (meaning f(x) = g(x) * h(x)), the derivative is f'(x) = g'(x)*h(x) + g(x)*h'(x). In simple language, the derivative is found by finding the derivative of x² + 1 and multiplying it with the normal function of x³ + 1, after which you add the product of the nnormal function of x² + 1 and the derivative of x³ + 1.

it might be clearer when I show you:

f(x) = (x^2 + 1)(x^3 + 1)\\f'(x) = (2x)(x^3 + 1) + (x^2 + 1)(3x^2)\\Simplify:\\f'(x) = 2x^4 + 2x + 3x^4 + 3x^2 = 5x^4 + 3x^2 + 2x\\

If you are not familiar with this rule you can first write out the function and then use the basic rule:

f(x) = (x^2 +1)(x^3+1) = x^5 + x^2 + x^3 + 1\\f'(x) = 5x^4 + 2x + 3x^2

If you need any further help please say so in the comments! I hope this helps! If the steps seem complicated, I suggest you could revise expanding brackets (the first step of the second method) and the basic rules of deriving, but feel free to reach out if you struggle afterwards still

8 0
2 years ago
I don’t know how to and i need answers pls
Assoli18 [71]

Answer:

n

Step-by-step explanation:

maybe not for sure

5 0
3 years ago
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