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noname [10]
3 years ago
5

A rectangle has length (x+4) cm and width (x-3) cm. Its area is 30 square centimeters. Write a quadratic equation and solve it t

o find the length of the rectangle.
Mathematics
1 answer:
Arturiano [62]3 years ago
6 0

(x+4)(x-3)=30

x^2 +x -12 =30

x^2 +x =42

x^2 +x -42 =0

(i solved it by factorising: _x^2 × -42)

x^2 -6x +7x -42 =0

x(x-6) +7(x-6) 0

(x-6)(x+7)=0

x=6; x=-7

since it's a length, x can't be a negative number, so it must be 6

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Step-by-step explanation:

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7 0
3 years ago
Solve -3y + 14 + y = 12
ser-zykov [4K]

Answer:

y = 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

-3y + 14 + y = 12

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Combine like terms [Addition]:                                                                        -2y + 14 = 12
  2. [Subtraction Property of Equality] Subtract 14 on both sides:                       -2y = -2
  3. [Division Property of Equality] Divide -2 on both sides:                                y = 1
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Step-by-step explanation:

Let black marbles be=2x

Then white marbles=5x

Total marbles=7x which in turn is equal to 35. Hence x=5

Black marbles=2*5=10

H2H

8 0
2 years ago
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