Answer:
29°; 61°
Step-by-step explanation:
Let one angle = x°
Other angle = (x + 32)°
x + x + 32 = 90 {given they are complementary}
2x + 32 = 90
2x = 90 -32
2x = 58
x = 58/2
x = 29
One angle = 29°
Other angle = 29 + 32 = 61°
In which language?
Please tell me the language java, c++, cetc?
Answer:
Answer is D.
Step-by-step explanation:
solution:
Consider the differential equation,
7ty + (1+t2)1/2y1 = 0
Rewrite the DE as,
(1+t2)1/2dy = - 7ty
dy/y = -7t/√1+t2 dt
in y = -7(1+t2) + c
y = ce-7(1+t2)
given,
y(0) = 1 => ce-7 = -1 => c = e7
ᴪ (t,y) = y -ce ᴪ(0,1)(1+t2)
9514 1404 393
Answer:
A x = 15
Step-by-step explanation:
Lines AB and CD being perpendicular means the angles where they meet are all 90°. The diagonal line divides two of those 90° angles into two parts (each). The whole (90°) is the sum of the parts into which the angle has been divided.
The sum of angles 3 and 4 is 90°. Once you understand this relationship, you can write an equation based on the relationship. The equation can be solved in the usual way.
(4x +4)° +26° = 90°
4x = 60 . . . . . . . . . . . . divide by °, subtract 30
x = 15 . . . . . . . . . . divide by 4
