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RideAnS [48]
2 years ago
13

A parallelogram has two 19-inch sides and two 23-inch sides. what is the range of possible lengths for the diagonals of this par

allelogram?
Mathematics
1 answer:
JulijaS [17]2 years ago
7 0

Answer:

hes correct

Step-by-step explanation:

lol

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Which value below is a solution to the inequality 4x - 5 > 37
ZanzabumX [31]

Answer:

3

Step-by-step explanation:

The answer to the question is x > 16

This shows that x is bigger than 16

4 0
2 years ago
Help helppp help i need answerr thank Uuuuuuuuu​
Galina-37 [17]

Answer:

see explanation

Step-by-step explanation:

(a)

The angles are vertical and congruent, that is

x - 10 = 125 ( add 10 to both sides )

x = 135

-------------------------------------------------

(b)

Supplementary angles sum to 180°

The angles are in the ratio 2 : 3 = 2x : 3x ( x is a multiplier ), then

2x + 3x = 180

5x = 180 ( divide both sides by 5 )

x = 36

thus

2x = 2 × 36 = 72

3x = 3 × 36 = 108

Then the 2 angles are 72° and 108°

3 0
2 years ago
Read 2 more answers
Which graphs have a positive average rate of change?
adelina 88 [10]

Answer:

Step-by-step explanation:

In general, graphs that go from lower left to upper right have a positive slope (think of it as going up the stairs...positive), and graphs that go from upper left to lower right have a negative slope (think of it as going down the stairs...negative).  I don't see graphs here but use this general idea and you'll be fine.  Of course, this applies to graphs of lines of the form y = mx + b.

4 0
3 years ago
What is the most precise classification of the quadrilateral formed by connecting the midpoints of the sides of a square?
e-lub [12.9K]
A square again
Lets take a is side of a square.
if u take parts of square from mid point and measure distance or length of any sides that would be a/2

then use Pythagorean theorem to solve hypotenuse u will get all length of small quadrilateral a/√2.same for all sides.
I see that will be square again
7 0
2 years ago
12. Find the area lying above the x - axis and below the parabolic curve y = 4x - x2.
Margarita [4]
First we find the zeroes so we don't take the integral of negative bits

4x-x²
x(4-x)
zeroes at x=0 and x=4
it opens down
so the part we are interested in is the bit between x=0 and x=4

\int\limits^4_0 {4x-x^2} \, dx =[2x^2- \frac{1}{3}x^3]^4_0=(32- \frac{64}{3})-(0)=  10.6666666666 or aout 10 and 2/3

C is answer
6 0
2 years ago
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