The equation is:
20,000 * e^(0.15 t) = 28,000
e^( 0.15 t ) = 28,000 : 20,000
e^( 0.15 t ) = 1.4
0.15 t = ln 1.4
0.15 t = 0.3365
t = 0.3365 : 0.15
t = 2.24 ≈ 2
Answer:
A ) 2 years.
Complete Question
Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150
Answer:
Normal sampling distribution can not be used
Step-by-step explanation:
From the question we are told that
The null hypothesis is 
The alternative hypothesis is 
The sample size is n= 150
Generally in order to use normal sampling distribution
The value 
So


Given that
normal sampling distribution can not be used
Because arcsin or sin-1 only gives outputs that are in the first and fourth quadrant.
5pi / 6 is in the second quadrant.
Answer:
4.9
Step-by-step explanation:
24.50 divided by 5 is 4.9
Answer:
Step-by-step explanation:
Alright, lets get started.
The probability that an event will occur is 2/3.
Means out of 3 times, 2 times that event will occur.
Please refer the pie chart for this, blue is the color which represents event to be occur and orange is not to be occur.
We can see, blue part is much more than orange part.
means the likelihood of event occuring is LIKELY. : Answer
Hope it will help :)