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2 years ago

Solve for x. 5x−2(x+1)=1/4 Enter your answer as a fraction in simplest form.

Mathematics

2 answers:

kondaur [170]2 years ago

6 0

Answer:

x= 3/4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

5x−2(x+1)= 1 /4

5x+(−2)(x)+(−2)(1)= 1 /4

(Distribute)

5x+−2x+−2= 1 /4

(5x+−2x)+(−2)= 1 /4

(Combine Like Terms)

3x+−2= 1 /4

3x−2=1 /4

Step 2: Add 2 to both sides.

3x−2+2= 1 /4 +2

3x= 9 /4

Step 3: Divide both sides by 3.

3x/ 3 = 9 /4 /3

x= 3 /4

beks73 [17]2 years ago

6 0

5x-2(x+1)=1/4
5x-2x-2=1/4
3x-2=1/4
3x=2 1/4
3x=9/4
3x/3=(9/4)/3
x=(9/4)(1/3)
x=9/12
x=3/4

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2 years ago

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vitfil [10]

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2 years ago

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2 years ago

ANSWER PLEASE FINAL DUE IN 3 HOURS

inna [77]

Answer:

Step-by-step explanation:

First thing to do here is to calculate the z-score

Mathematically;

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3 years ago

How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l

musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - α) % confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The margin of error in this interval is:

$MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The formula to compute the sample size is:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}$

(1)

Given:

$\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97$

Thus, the minimum sample size required is 97.

(2)

Given:

$\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385$

Thus, the minimum sample size required is 385.

(3)

Given:

$\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use the z-table for the critical value.

Compute the value of n as follows:

$\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604$

Thus, the minimum sample size required is 9604.

8 0

2 years ago

​Solve for x. 5x−2(x+1)=1/4 ​ Enter your answer as a fraction in simplest form.

Solve for x. 5x−2(x+1)=1/4 Enter your answer as a fraction in simplest form.