S the interquartile range of this data?
1 answer:
We have been given the 5-number summary of a box plot that represents Coins in Collection. The five-number summary from left to right is 7, 16, 30, 36, 38.
We are asked to find the inter-quartile range of the given data.
We know that interquartile range is difference of upper quartile and lower quartile.
We know that the 5-point summary represents the lower data point, lower quartile, median, upper quartile and upper data point respectively.
We can see from our given 5 point-summary that lower quartile is 16 and upper quartile is 36.
Therefore, the interquartile range of the given data is 20 and last option is the correct choice.
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Answer:
The answer is below
Step-by-step explanation:
The diameter of a tire is 2.5 ft. a. Find the circumference of the tire. b. About how many times will the tire have to rotate to travel 1 mile?
Solution:
a) The circumference of a circle is the perimeter of the circle. The circumference of the circle is the distance around a circle, that is the arc length of the circle. The circumference of a circle is given by:
Circumference = 2π × radius; but diameter = 2 × radius. Hence:
Circumference = π * diameter.
Given that diameter of the tire = 2.5 ft:
Circumference of the tire = π * diameter = 2.5 * π = 7.85 ft
b) since the circumference of the tire is 7.85 ft, it means that 1 revolution of the tire covers a distance of 7.85 ft.
1 mile = 5280 ft
The number of rotation required to cover 1 mile (5280 ft) is:
number of rotation =