Answer:
Circumference= 44 in
Area= 154 in²
Step-by-step explanation:
![\boxed{circumference \: of \: circle = 2\pi r}](https://tex.z-dn.net/?f=%5Cboxed%7Bcircumference%20%5C%3A%20of%20%5C%3A%20circle%20%3D%202%5Cpi%20%20r%7D)
Radius
= diameter ÷2
= 14 ÷2
= 7 in
Circumference of circle
![= 2( \frac{22}{7} )(7)](https://tex.z-dn.net/?f=%20%3D%202%28%20%5Cfrac%7B22%7D%7B7%7D%20%29%287%29)
= 44 in
![\boxed{area \: of \: circle = \pi {r}^{2} }](https://tex.z-dn.net/?f=%5Cboxed%7Barea%20%5C%3A%20of%20%5C%3A%20circle%20%3D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20%7D)
Area of circle
![= \frac{22}{7} ( {7}^{2} )](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B22%7D%7B7%7D%20%28%20%7B7%7D%5E%7B2%7D%20%29)
= 154 in²
Answer:
Maybe 180° -50° = 130°
So I think x= 130°
Step-by-step explanation:
My opinion though
Answer:
2greater then or equal to x 5 greater then or equal to
Let JD = Distance drilled in joist
<span>JD = 3 - 1 1/3 </span>
<span>JD = 9/3 - 4/3 </span>
<span>========================== </span>
<span>JD = 5/3 or 1 2/3 in ◄ Ans
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