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Andrew [12]
3 years ago
12

Find all the zeros of the equation. Need help finding the zeros.

Mathematics
1 answer:
marta [7]3 years ago
6 0
Given the expression
-3x^4+27x^2+1200=0
let x^2=a
we can re-write our expression as:
-3a^2+27a+1200=0
-3(a^2-9a-400)=0
a^2-9a-400=0
factorizing the above we have:
a^2+16a-25a-400=0
a(a+16)-25(a+16)=0
(a+16)(a-25)
thus replacing back x^2 we have:
(x^2+16)(x^2-25)
=(x^2+16)(x-5)(x+5)
factorizing (x^2+16) we get
x^2=+/-√-16
x=+/-4i
thus the zeros of the expression are:
x=-5, x=5 , x=-4i, x=4i

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Answer:

c = 41

Step-by-step explanation:

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c =  \sqrt{ {a}^{2} +  {b}^{2}  }

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Each scenario can be used to simulate probability, and there are 3 correct scenarios and 2 incorrect scenarios in the list of options

<h3>How to categorize the simulations?</h3>

From the question, we have the following parameters:

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Using the above highlights, the correct scenarios are:

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3 years ago
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