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3 years ago

For what value of x is the rational expression below equal to zero

Mathematics

1 answer:

Elena L [17]3 years ago

8 0

X = 2

S P A C E F I L L E R L O L

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2. Graph each equation using a table of values.<br> (a)) y = 3x - 1

kiruha [24]

Make an x and y table, and pick any values to plug in for x in the equation.

I will use the numbers from -2 to 2

Now plug in the values you picked for x into the equation to find its y-value

x = -2

y = 3x - 1 Plug in -2 for x

y = 3(-2) - 1

y = -6 - 1

y = -7

x = -1

y = 3x - 1

y = 3(-1) - 1

y = -3 - 1

y = -4

Do the same for the rest of the numbers, and graph each point and draw a line connecting them.

6 0

3 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

5 3/11 as a decimal rounded to the nearest hundredth

valentinak56 [21]

Answer:

5.27

Step-by-step explanation:

3 divided by 11 is 0.272727272727272727 or 0.27

add 5 and 0.27

5 0

3 years ago

Read 2 more answers

How do u regroup when u find the sum of 64+43

Anarel [89]

What we are going to do is use the DISTRIBUTIVE PROPERTY. This distributive the numbers, to make it easier to solve.

So we will break 64 up.

64 = 60 + 4

43 = 40 + 3

60 + 40 = 100

4 + 3 = 7

100 + 7 = 107

So, 64 + 43 = 107.

Hope I helped ya!!!!!!!

6 0

3 years ago

Read 2 more answers

Need help kinda stuck on this one!

irinina [24]

It goes zero positive negative. that is from left to right

6 0

3 years ago