Answer:
3.2
Step-by-step explanation:
x² + xy = 20
Take the derivative with respect to time:
2x dx/dt + x dy/dt + y dx/dt = 20
(2x + y) dx/dt + x dy/dt = 20
Given x = -5, y = 1, and dx/dt = -4:
(2(-5) + 1) (-4) + (-5) dy/dt = 20
(-10 + 1) (-4) − 5 dy/dt = 20
36 − 5 dy/dt = 20
5 dy/dt = 16
dy/dt = 3.2
1 coin has 2 sides. Multiply 2 × 3 to get the total number of outcomes.
2 × 3 = 6
There are 3/6 Possible outcomes.
Remember, they are looking for the number of heads, not both.

<u>We </u><u>have </u><u>given </u><u>in </u><u>the </u><u>question </u><u>that</u><u>, </u>
- <u>The </u><u>sum </u><u>of </u><u>2</u><u> </u><u>numbers </u><u>is </u><u>equal </u><u>to </u><u>1</u><u>1</u><u> </u>
- <u>The </u><u>difference </u><u>between </u><u>two </u><u>numbers </u><u>is </u><u>1</u><u>9</u><u> </u><u>.</u>

- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y</u><u>. </u>

Let the two numbers be x and y
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>


<u>Solving </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>


<u>Subsituting </u><u>eq(</u><u>3</u><u> </u><u>)</u><u> </u><u>in </u><u>eq</u><u>(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>









<u>Now</u><u>, </u><u> </u><u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>3</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>




Hence, The value of x and y are 15 and (-4) .
Answer:(-2,7)
Step-by-step explanation:
It depends on what level of classes you take, but algebra classes in college do tend to be harder than algebra classes in high school or middle school.