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DedPeter [7]
3 years ago
15

How do you solve and graph this inequality

Mathematics
1 answer:
frozen [14]3 years ago
8 0
Step 1: Cross multiply making it
<u>5 (2t+1)</u> <span>> <u>  9(t)    </u></span>
 t(2t+1)     (t) 2t+1

Step 2: Now that the denominators are the same, we can make simplify it by dividing it by 't (2t+1)'
5(2t+1) > 9(t)

Step 3: Remove parenthesis 
10t+5 > 9t

Step 4: Isolate t
10t>9t-5
t > -5 (FINAL ANSWER)
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Pre-Calc: Find all the zeros of the function.
uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Read more about polynomial at

brainly.com/question/17517586

#SPJ1

5 0
1 year ago
Is 2(x-5)=5x+23 a true or false equation ​
sergiy2304 [10]
False ......................................
5 0
2 years ago
Read 2 more answers
An equation has solutions of m= -5 and m=9. Which would be the equation?
Aliun [14]

Answer:

There could be many but one of them is

(m+5)(m-9)=0....

7 0
3 years ago
Read 2 more answers
I need help on 12 and 16
krok68 [10]
12. A trapezoid is a quadrilateral. It has 4 sides


16. Two parallelograms. Two sides opposite of each other will be parallel to each other. The same is true with the other two sides. (length and width)
7 0
3 years ago
A circle has a sector with area 33 pi and a central angle of 11/6 pi radians. What is the area of a circle?
Mashutka [201]

Answer:

36π

Step-by-step explanation:

The area of a circle is given as:

A = \pi r^2

where r = radius of the circle

The area of a sector of a circle is given as:

A_s = \frac{\alpha }{2\pi} * \pi r^2

where α = central angle in radians

Since \pi r^2 is the area of a circle, A, this implies that:

A_s = \frac{\alpha }{360}  * A

A circle has a sector with area 33 pi and a central angle of 11/6 pi radians.

Therefore, the area of the circle, A, is:

33 \pi = \frac{\frac{11 \pi}{6} }{2 \pi} * A\\\\33\pi = \frac{11}{12} * A\\\\=> A = \frac{33\pi * 12}{11}\\ \\A = \frac{396 \pi}{11} \\\\A = 36\pi

The area of the circle is 36π.

5 0
2 years ago
Read 2 more answers
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