No: of blue pens =4
No: of red pens= 3
black pens=twice as many blue pens
=2(4)=8
total no: of pens= 4+3+8
=14
therefore the fraction required will be =4/15

HOPE THIS HELPS ! :)

7 0

3 years ago

How do I solve circumference and areas of circles?

vaieri [72.5K]

Radius squared times pie
and diameter squared times pie

4 0

2 years ago

Read 2 more answers

Como se resuelve esto? 3x²+10x=O

Arturiano [62]

3 x^2 + 10 x = 0

x ( 3 x + 10 ) = 0

x = 0 or 3 x+ 10 = 0

x = 0 or 3 x = -10

x = 0 or x = -10/3

6 0

1 year ago

The equation of a circle is given below. Identify the radius and center.

bonufazy [111]

Answer:

The center is (3,1) and the radius is 3.

Step-by-step explanation:

The goal is to write in $(x-h)^2+(y-k)^2=r^2$ because this tells us the center (h,k) and the radius r.

So we are going to need to complete the square 2 times here, once for x and the other time for y.

I'm going to use this formula to help me to complete the square:

$x^2+bx+(\frac{b}{2})^2=(x+\frac{b}{2})^2$ .

So first step:

I'm going to group my x's together and my y's.

$x^2-6x+\text{ ___ }+y^2-2y+\text{ ___ }+1=0$

Second step:

I'm going to go ahead and subtract that one on both sides. Those blanks are there because I'm going to fill them in with a number so that I can write the x part and y part as a square. Remember whatever you add on one side you must add on the other. So I'm going to put 2 more blanks to fill in on the opposite side of the equation.

$x^2-6x+\text{ ___ }+y^2-2y+\text{ ___ }=-1+\text{ ___ }+\text{ ___}$

Third step:

Alright first blank I'm putting (-6/2)^2 due to my completing the square formula. That means this value will also go on the other side in on of those blanks.

In the second blank I'm going to put (-2/2)^2 due to the completing the square formula. This must also go on one of the blanks on the other side.

So we have:

$x^2-6x+(\frac{-6}{2})^2+y^2-2y+(\frac{-2}{2})^2=-1+(\frac{-6}{2})^2+(\frac{-2}{2})^2$