Answer: Question 1
a)5.47
b)4.53
Step-by-step explanation:
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
We have that the fourth term of an arithmetic sequence is
a_4=14
Option C
From the question we are told
What is the fourth term of an arithmetic sequence whose first term is 23 and whose seventh term is 5?
A) 78
B) 32
C) 14
(Explain your work)
Generally the equation for the arithmetic sequence is mathematically given as

Therefore
For seventh term

Therefore
For Fourth term

a_4=14
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Answer: C
Step-by-step explanation:
Simplify the expression to 2^1/4
Now transform the expression using a^m/n = n root a raised to a power of m.
And that's how you get your answer.