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baherus [9]
3 years ago
5

Which function is graphed below?

Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0

Answer:

g(x)=\sqrt{x+2}

Step-by-step explanation:

Parent function of the given graph is,

f(x) = \sqrt{x}

If the parent function is shifted 2 units to he left the new function or image function will be,

g(x) = \sqrt{x+2}

Therefore, graph will represent the graph of the function g(x) = \sqrt{x+2}.  

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Find the area of a regular hexagon with the measurement 4- inch side
olga2289 [7]
The answer is 24 root 3 or 41.56921938.
6 0
3 years ago
(6y^2-7y-3)-(2y^2-9y-7) simplify
madreJ [45]
6y^2-7y-3-2y^2+9y+7 (pretend that you're multiplying -1 to 2y^2-9y-7 which is why 9y and 7 are positive now).
Now you're able to simplify your problem, so...

6y^2-2y^2= 4y^2
-7y+9y= 2y
-3+7=4

4y^2+2y+4

Might want to check my math but that's how you do it.
5 0
3 years ago
What is the median of the following numbers?<br> 9,8,1, 8,5
Zolol [24]

Answer:

8

Step-by-step explanation:

1, 5, 8, 8, 9

Find the middle number. If there is 2 add them and divide them by 2

But there is 1 middle number 8

3 0
3 years ago
What is ​ BC ​ ? <br><br> Enter your answer in the box.<br><br> units
Vladimir79 [104]

Answer:

BC = 25

Step-by-step explanation:

AB = AC since it is an isosceles triangle

4x+1 = 2x+23

subtract 2x from each side

4x-2x+1 = 2x-2x+23

2x +1 = 23

subtract 1 from each side

2x+1 -1 = 23-1

2x = 22

divide by 2

2x/2 =22/2

x =11

BC = 3x-8

BC = 3(11) -8

BC =33-8

BC = 25


6 0
3 years ago
At the beginning of year 1, Josie invests $400 at an annual compound interest
zvonat [6]

Answer:

The explicit formula that can be used is A=\$400(1.05)^{2}

The account's balance at the beginning of year 3 is A=\$441  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=2\ years\\ P=\$400\\ r=0.05\\n=1  

substitute in the formula above  

A=\$400(1+\frac{0.05}{1})^{1*2}  

A=\$400(1.05)^{2}

A=\$441  

3 0
3 years ago
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