Hence,
How can you use a ratio table to find the value of x in the ratio x:20 if the ratio is equivalent to 5:2
1 answer:
You might be interested in
Answer:
x = 1
Step-by-step explanation:
Answer:
360,360 groups of 5 people.
Step-by-step explanation:
We have been given that there are 15 people in an office with 5 different phone lines. We are asked to find groups of 5 people that can answer these lines, if all the lines begin to ring at once.
We will use fundamental principle of counting to solve our given problem.
There are 15 people to answer 1st line, that will leave us with 14 people to answer 2nd line.
Now, we will have 13 people to answer 3rd line, that will leave us with 12 people to answer 4th line.
There are 11 people to answer 5th call.
So 5 lines can be answered in ways.
Therefore, 360,360 groups of 5 people can answer these lines.
Answer:
The proportion of college students who work year-round is 58%.
Step-by-step explanation:
The claim made by the education researcher is that 58% of college students work year-round.
A random sample of 400 college students, 232 say they work year-round.
To test the researcher's claim use a one-proportion <em>z</em>-test.
The hypothesis can be defined as follows:
<em>H</em>₀: The proportion of college students who work year-round is 58%, i.e. <em>p</em> = 0.58.
<em>Hₐ</em>: The proportion of college students who work year-round is 58%, i.e. <em>p</em> ≠ 0.58. C
Compute the sample proportion as follows:
Compute the test statistic value as follows:
The test statistic value is 0.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected.
Compute the p-value for the two-tailed test as follows:
*Use a z-table for the probability.
The p-value of the test is 1.
The p-value of the test is very large when compared to the significance level.
The null hypothesis will not be rejected.
Thus, it can be concluded that the proportion of college students who work year-round is 58%.