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mario62 [17]
3 years ago
9

Find the value of x y and z​

Mathematics
1 answer:
poizon [28]3 years ago
5 0
I think you can plus like 180 plus that or 180 minus butttt it’s bc the angle looks like a “C” so you plus
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Please I need help quick
mafiozo [28]
The ratios are both identical

sin x = perpendicular/hypotenuse = 3/5
cosy = base/hypotenuse = 3/5
4 0
3 years ago
Read 2 more answers
5/100 as a decimal in Dollar form
mina [271]

Answer:

$0.05

Step-by-step explanation:

Hope it helps and have a great day =D

5 0
2 years ago
Read 2 more answers
What is the slope of the line passing through the points (0,0),(1/3,7/3)?
umka21 [38]
(0,0)(1/3,7/3)

slope = (7/3 - 0) / (1/3 - 0) = (7/3) / (1/3) = 7/3 * 3 = 21/3 = 7 <==
8 0
3 years ago
Someone please help me !!! i need it by 7:30!! ammm!!!
AveGali [126]

Answer:

LON and MLN are both equal to 126 degrees,

since the angles with the value '4x + 7' and '7x - 35' degrees are equal to each other, you can rewrite it like this:

4x+7=7x-35

now, take the 7x away from both sides:

-3x+7=-35

then, subtract 7 from both sides:

-3x=-42

now, divide both sides by -3:

x=14

now that we know the value of x (14), we can plug it into the expressions.

4(14)+7=63

7(14)=63

add them together to find the angle MLN

and since the opposite angle (LON) is equal to MLN, they both = 126 degrees

hope this helped :)

8 0
2 years ago
The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0
3 years ago
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