The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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Answer:
271 boxes
Step-by-step explanation:
Answer:
2.4 hr. = time working together
Step-by-step explanation:
Let x = time working together
x/6 = work done by Martin
x/4 = work done by Victor
Martin's part + Victor's part = 1 jog done
x/6 + x/4 = 1 Multiply thru by 12
2x + 3x = 12
5x = 12
x = 2.4 hr.
5,000 - bag of fertilizer
500 - Mike’s lawn
3/4 - applied fertilizer
4 - frequency in 1 year
(500 x 3/4 )x 4
(1500 / 4 ) x 4
1500 sqm / yr
5,000 sqm / 1500sqm/yr
3.33 yr
He will be able to fertilize it in 3 full years
Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:
First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;
Divide by m to isolate 
.
To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
