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weeeeeb [17]
4 years ago
8

NEED HELP ASAP. Check my answer

Mathematics
2 answers:
lisabon 2012 [21]4 years ago
6 0

that looks like a regular octagon to me

Flauer [41]4 years ago
6 0

Answer:B Octagon regular

Step-by-step explanation:

Because an Octagon has 8 sides

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Alexandra complete 40 percent of a 50-question assignment.how many questions did she complete?.
Georgia [21]
She answered 20 questions
3 0
3 years ago
The weight of 8 science books is 28 pounds. What is the weight of 11 science books?
n200080 [17]
First,divide 28 divided by 8 which is 3.5
then,multiply your answer (3.5) times the 11 books.

so 3.5 times 11 which equals 38.5
8 0
3 years ago
Electric charge is distributed over the rectangle 2 ≤ x ≤ 4, 0 ≤ y ≤ 2 so that the charge density at (x, y) is σ(x, y) = 2xy + y
dybincka [34]

Answer:

The total charge on the rectangle is 29.33C

Step-by-step explanation:

Given

σ(x, y) = 2xy + y²

For 2 ≤ x ≤ 4, 0 ≤ y ≤ 2

The total charge on the rectangle is calculated as follows.

Charge, q = ∫∫2xy + y² dydx {0,2}{2,4}

Integrate with respect to y

q = ∫xy² + ⅓y³ dydx {0,2}{2,4}

q = ∫(2²*x + ⅓*2³) dx {2,4}

q = ∫4x + 8/3 dx {2,4}

Integrate with respect to x

q = 2x² + 8x/3 {2,4}

q = (2(4)² + 8(4)/3) - (2(2)² + 8(2)/3)

q = 29.33C

7 0
4 years ago
Read 2 more answers
Can someone help me please.<br>Can someone FIND LENGHT OF c​
olasank [31]

Answer:

c = 50

Step-by-step explanation:

Use the Pythagorean Theorem:

a^2+b^2=c^2

14^2+48^2=c^2

2500=c^2

\sqrt{2500} =c

50=c

4 0
3 years ago
John’s Bar is 60 km away from Ben’s Bar. Doug’s Bar is 40 km away from Kieran’s Bar. John’s Bar is 10 km nearer to Doug’s Bar th
soldier1979 [14.2K]
If we let x be the distance from John's Bar to Doug's bar then we can derive the expression,
                                (x - 10) + x = 40
The value of x from the equation is 25. This means that the distance between John's bar and Dough's bar is 15 km. Since, John's bar and Ben's bar are 60 km apart, the distance between Doug's bar and Ben's bar is 45 km. 
3 0
3 years ago
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