Help! I can’t solve this equation....
1 answer:
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<h2>Answer with explanation:</h2>
We know that a removable discontinuity occurs when:
The left and the right hand limit of the function exist at a point and are equal but is unequal to the function's value at that point.
Also it is a point on the graph such that it is undefined at that point.
The graph that has a removable discontinuity is attached to the answer.
Since, at x=0 the left hand and the right hand limit of the function exist but the function is not defined at x=0 , since in the graph there is a open circle at x=0 that means that the point is removed from the range.