Answer:


Step-by-step explanation:
<h3>Question-1:</h3>
so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,
to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

to solve the equation can consider the quadratic formula given by

so let our a,b and c be -4.9,229 and 346 Thus substitute:

remove parentheses:

simplify square:

simplify multiplication:

simplify Substraction:

by simplifying we acquire:

since time can't be negative

hence,
at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs
<h3>Question-2:</h3>
to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

let a and b be -4.9 and 229 respectively thus substitute:

simplify which yields:

now plug in the maximum t to the function:

simplify:

hence,
about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?
I’m not sure but i think it is 126 pi IM SORRY IF IM WRONGGGGG
Step-by-step explanation:
A) 3x + 8 = 23
3x = 23 - 8
3x = 15
x = 15 / 3 = 5
B) 5x + 1 = 3x + 17
5x - 3x = 17 - 1
2x = 16
x = 16 /2 = 8
C) 4 (x+2) = 32
4x + 8 = 32
4x = 32 - 8
4x = 24
x = 24 / 4 = 6
Let's call the width: w
the lenght is then 3w+4 ("4 more than 3 times the width")
and the parameter would be 2(w+3w+4), that is 2*(4w+4), that is 8w+8.
this is also equal to 18.4:
8w+8=18.4
8w=10.4
w=1.3
this is the width, and the lenght is:
4+3*1,3=4+3.9=7.9
and the area is their product:
1.3*7.9=10.27
Answer:
[y]
-16
-12
0
12
16
Step-by-step explanation:
Put the x value in the equation to find your answer