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Katen [24]
3 years ago
10

Solve 7/4=n/32 whats n?

Mathematics
2 answers:
alexandr402 [8]3 years ago
8 0
N= 56.

Multiply 7/4 by 32 then divide it so it would be

224/4 = n
Mrac [35]3 years ago
7 0
I hope this helps you




7.32=4.n



n=7.32/4



n=7.8



n=56
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Find the equation of a line passing through (-4,-3) and perpendicular to<br> 3 x + 2 y = 14.
Reil [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

3x+2y=14\implies 2y=-3x+14\implies y=\cfrac{-3x+14}{2}\implies y = \cfrac{-3x}{2}+\cfrac{14}{2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{2}}x+7\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so therefore

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-3}{2}} ~\hfill \stackrel{reciprocal}{\cfrac{2}{-3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{2}{-3}\implies \cfrac{2}{3}}}

so we're really looking for the equation of a line whose slope is 2/3 and passes through (-4 , -3)

(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{2}{3}}(x-\stackrel{x_1}{(-4)}) \implies y+3=\cfrac{2}{3}(x+4) \\\\\\ y+3=\cfrac{2}{3}x+\cfrac{8}{3}\implies y=\cfrac{2}{3}x+\cfrac{8}{3}-3\implies y=\cfrac{2}{3}x-\cfrac{1}{3}

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2 years ago
Need help, this is 7th grade, will be 50 points for work shown
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Answer:

.111      11.1%

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Step-by-step explanation:

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EastWind [94]
His salary would be 474,720$
4 0
3 years ago
The question is below
saul85 [17]

Answer:

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Step-by-step explanation:

The sum of the angles in a triangle are 180 degrees. The angles look the same size, so divide 180 by 3, and you get 60 degrees

7 0
3 years ago
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A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 1:4.
schepotkina [342]

Let point C has coordinates (x_C,y_C). Consider vectors

\overrightarrow{AB}=(x_B-x_A,y_B-y_A)=(8-9,6-9)=(-1,-3),\\ \\\overrightarrow{BC}=(x_C-x_B,y_C-y_B)=(x_C-8,y_C-6).

Since the ratio AB to BC is 1:4, you have that

\dfrac{-1}{x_C-8}=\dfrac{1}{4}\quad \text{and}\quad \dfrac{-3}{y_C-6}=\dfrac{1}{4}.

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Answer: C(4,-6)

7 0
3 years ago
Read 2 more answers
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