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Katen [24]
3 years ago
10

Solve 7/4=n/32 whats n?

Mathematics
2 answers:
alexandr402 [8]3 years ago
8 0
N= 56.

Multiply 7/4 by 32 then divide it so it would be

224/4 = n
Mrac [35]3 years ago
7 0
I hope this helps you




7.32=4.n



n=7.32/4



n=7.8



n=56
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megans insurance company pays for 90% of her knee surgery after she pays an $800 deductible how much will Megan pay for surgery
algol [13]

Answer:

Megan will have to pay $2, 260 for surgery.

Step-by-step explanation:

1. Translate percent into decimal:

90% -> 0.9

2. Multiply (to find out how much the insurance company pays):

(0.9)(14, 600) = 13, 140

3. Subtract:

14, 600 - 13, 140 = 1, 460

4. Add (to find out how much Megan pays):

1, 460 + 800 = 2, 260


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3 years ago
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Nadusha1986 [10]
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3 years ago
(I need the answer right now please) ΔA'B'C' was constructed using ΔABC and line segment EH. 2 triangles are shown. Line E H is
irina1246 [14]

Answer:

The true statements are

1. BD = DB'

3. m∠EFA = 90°

4. The line of reflection, EH, is the perpendicular bisector of BB', AA', and

   CC'

Step-by-step explanation:

* Lets explain how to solve the problem

- Reflection is flipping an object over the line of reflection.

- The object and its image have the same shape and size, but the

  figures are in opposite directions from the line of reflection

- The objects appear as if they are mirror reflections, with right and left

  reversed

- The line of reflection is a perpendicular bisector for all lines joining

  points on the figure with their corresponding images

- Look to the attached figure for more understand

* Lets solve the problem

- ΔA'B'C' was constructed using ΔABC and line segment EH, where

 EH is the reflection line

- D is the mid-point of BB'

- F is the mid-point of AA'

- G is the mid-point of CC'

* Lets find from the answer the true statements

1. BD = DB'

∵ D is the mid point of BB'

- Point D divides BB' into two equal parts

∴ BD = DB' ⇒ <em>True</em>

2. DF = FG

- It depends on the size of the sides and angles of the triangle

∵ We can't prove that

∴ DF = FG ⇒ <em>Not true</em>

3. m∠EFA = 90°

∵ The line of reflection ⊥ the lines joining the points with their

   corresponding images

∴ EH ⊥ AA' and bisect it at F

∴ m∠EFA = 90° ⇒ <em>True</em>

4. The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC'

- Yes the line of reflection is perpendicular bisectors of them

∴ The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC' ⇒ <em>True</em>

5. ΔABC is not congruent to ΔA'B'C'

∵ In reflection the object and its image have the same shape and size

∴ Δ ABC is congruent to Δ A'B'C'

∴ ΔABC is not congruent to ΔA'B'C' ⇒ <em>Not true</em>

4 0
3 years ago
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Simple math equation but in not very bright in the head, help would be appreciated :)
algol [13]

Answer:

AA similarity

Step-by-step explanation:

Using angle sum theorem, you can clearly find out the missing angles on the left and right triangles are 40° and 50° respectively.

Therefore, by using any two angles in the triangles, you can prove they are similar by AA similarity.

4 0
2 years ago
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