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erica [24]
3 years ago
9

Find the length of the indicated side.

Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0

Hello

DEF and IKL , equilateral  =>

DE = 5x-12 = 3x-4

5x-3x= -4+12

2x= 8

x=4

DE = 5x-12 =  20-12 = 8

KL = 3x+24 = 10x+3

24 -3 = 10x-3x

21 = 7x

x= 21/7 = 3

KJ = 10x+3 = 30+3 = 33

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What is the tangent ratio?
Xelga [282]

Answer:

The answer is opposite/adjacent

Step-by-step explanation:

Based on this saying that SohCahToa

Which means sin=opposite/hypotenuse

Cos=adjacent/hypotenuse

Tan=opposite/adjacent

The opposite is the side facing the right angle

The hypotenuse is the longest side of the triangle

The adjacent is the line that has both the right angle and opposite angle

6 0
2 years ago
Law of sines and cosines <br>how do I do this question when it is not SSS, SAS, ASA, or AAS.
Viktor [21]
<span>To solve a triangle using law of sines you must have the length of one side and the measure of the angle opposite that particular side. Then you must have one other piece of information, either one more side length or one more angle measurement. However in some cases when the information you are given is two consecutive sides, and the angle is not between the two consecutive sides, then there exists the possibility that there are two different triangles that will satisfy the given information.</span>
6 0
2 years ago
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar and ^ to indicate an
tatiyna

Answer:

7m(3m^6 - m^4 + 7)

Step-by-step explanation:

This is a factorization question

All we want to do here is to factor out 7m from each term of the polynomial

This becomes;

21m^7 -7m^5 + 49m = 7m (3m^6 - m^4 + 7)

4 0
3 years ago
Two rectangular adjacent rooms share a wall 1‘ x 1‘ tiles cover the floor of each room describe how the greatest possible length
cestrela7 [59]

Answer:

Consider two adjacent rectangular rooms having Length=L, and, Breadth = B

Now Suppose the wall which is in between two rooms has a height or length =H.

Breadth of wall = B [ if the wall doesn't exceed the breadth of room]

Considering two rooms to be identical,

Area of each room= L × B square unit

Area of each tile = 1×1=1 square unit

Number of tiles required= L B ÷ 1= LB tiles( product of length and breadth of room is number of tiles required)

Suppose if,LB= N

B= N/L  .................(1)

Area of wall(W) = B×H= B H square unit

B =W/H ......................(2)

Equating (1) and (2)

⇒N/L = W/ H

⇒H =\frac{WL}{N}

⇒H =\frac{WL}{LB}

⇒H = W/B

 ⇒  H =\frac {\text{ Area of Wall}}{\text{Breadth of room or wall}}




5 0
3 years ago
(URGENT-15 Points) Can someone help me/check my answers for this? Thank you! For the first screenshot, my answers for 1-5 are: (
Lisa [10]
1.  81.72
2.  10.37
3.  81.72 + 10.37 = 92.09  81.72 - 10.37 = 71.35
4.  81.72 + 2(10.37)= 102.46  81.72 - 2(10.37) = 60.98
5. 81.72 + 3(10.37) = 112.83  81.72-3(10.37) = 50.61
6. no
7. It is not bell-shaped
8.  P(>=90) = 15/50 = 3/10 = 30%; 2nd way??
9.  5 = 68, 12 = 72, 24 = 82, 35 = 89, 43 = 92
10. 80.6
11.  no
12.  The population mean includes all of the data values and the sample mean only includes the 5 data values.
4 0
3 years ago
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