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Sholpan [36]
4 years ago
6

N circle o, radius oq measures 9 inches and arc pq measures 6π inches. what is the measure, in radians, of central angle poq? 2p

i/3 radians 3pi/4 centimeters 4pi/3 radians 3pi/2 radians
Mathematics
2 answers:
LuckyWell [14K]4 years ago
6 0

Answer: \frac{2\pi}{3} radians

Step-by-step explanation:

Given: In circle O, the radius of circle = 9 inches

The arc length of PQ= 6\pi inches

Let \theta be the measure of the angle .

The formula to calculate arc length(l) for radius r and angle x is given by :-

l=r*\x\\\\\Rightarrow\ x=\frac{l}{r}

According to the question we have,

\theta=\frac{6\pi}{9}=\frac{2\pi}{3}

Hence, the measure, of central angle POQ= \frac{2\pi}{3} radians

nalin [4]4 years ago
5 0
 θ = 6π/9 =  2π/3  radians

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THE QUESTION CAN BE WRITTEN AS THIS;

It is given that ∠ABC and ∠CBD are a____________ So, m∠ABC+m∠CBD=90° using the b____________. It is also given that ​m∠ABC=35°​. Using the substitution property of equality, you have c________+ ​m∠CBD=90°​. Therefore, using the subtraction property of equality, ​m∠CBD=55°

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PLEASE CHECK THE ATTACHED FIGURE TO SEE HOW THE QUESTION LOOKS LIKE

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