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siniylev [52]
3 years ago
6

PLS HELP ASAP IW ILL GIVE BRIANLEST IF RIGHT DO NOT ANSWER UNUSEFUL ANSWERS

Mathematics
2 answers:
Viefleur [7K]3 years ago
6 0
1- 0.46
2-0.4
3-0.6
4-0.8
Roman55 [17]3 years ago
4 0

1 equals 0.46 (make a line over the 6 to show it is repeated)

2 equals 0.4 (make a line over the 4 to show it is repeated)

3 equals -0.6 (make a line over the 6 to show it is repeated)

4 equals -0.857142 (make a line over all numbers past the decimal to show it is repeated)

5 equals 3.3409 (make a line over the 09 at the end to show it is repeated)

6 equals -1.7727 (make a line over the 27 at the end to show it is repeated)

7 equals 66.5%

8 equals 3.16 (make a line over the 6 to show it is repeated)

9 equals -9 over 10

10 equals -17 over 20

11 equals -3 and 4 over 5

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In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per
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Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, P_0=450,000

Growth rate is, r=5\%=0.05

Final population is, P=700,000

A population growth is an exponential growth and is modeled by the following function:

P=P_0(1+r)^x

Taking log on both sides, we get:

\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}

Plug in all the given values and solve for 'x'.

x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10

So, for x > 9.13, the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0
3 years ago
How do kids get suspended from virtual school? and also whats 5-14+0=
andrey2020 [161]

Answer:

-9

Step-by-step explanation:

5 - 14 = -9

-9 + 0 = -9

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