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Margarita [4]
3 years ago
13

Helpppppp fasttttttttttt

Mathematics
1 answer:
bija089 [108]3 years ago
5 0

Answer:

60 wpm

Step-by-step explanation:

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Jason went to the post office and bought both 41-cent stamps and 26-cent postcards and spent $10.28. The number of stamps was 4
Charra [1.4K]
<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>

<em><u>Solution:</u></em>

Let stamps be s and postcards be p

Given that,

The number of stamps was 4 more than twice the number of postcards

s = 4 + 2p -------- eqn 1

Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28

41 cent = $ 0.41

26 cent = $ 0.26

Therefore,

s \times 0.41 + p \times 0.26 = 10.28

0.41s + 0.26p = 10.28 --------- eqn 2

Substitute eqn 1 in eqn 2

0.41(4 + 2p) + 0.26p = 10.28

1.64 + 0.82p + 0.26p = 10.28

1.08p = 10.28 - 1.64

1.08p = 8.64

Divide both sides by 1.08

p = 8

Substitute p = 8 in eqn 1

s = 4 + 2(8)

s = 4 + 16

s = 20

Thus Jason bought 20 stamps and 8 post cards

8 0
3 years ago
3(4x+5)=33 What’s the value of x
atroni [7]

Answer:

the answer would be 20

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Answer:

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Step-by-step explanation:

Y=mx+b

M=\frac{x2-x1}{y2-y1}

M=\frac{0-(-4)}{-10-3}

M=\frac{-4}{-7}

Y=(\frac{4}{7}) x+2

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