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Talja [164]
3 years ago
6

How do you find the asymptote of a function

Mathematics
1 answer:
inn [45]3 years ago
4 0
There are two types of aymptotes; horizontal and vertical asymptote. To find asymptotes of a function, you first must know the domain and range of the given function. Let's say the function is:
f(x) = \frac{x + 2}{x - 2}
Horizontal Asymptote:
To find this asymptote, we have to look at the domain (or the denominator). The domain will be: x such that x is not = to 2. This is because the denominator is x-2, and if you substitute x with 2 it will be 2-2=0. But, anything divided by 0 is undefined. To find the asymptote,you take the denominator itself;
x - 2
x = 2 \: will \: be \: the \: horizontal \: asymptote
Vertical Asymptote:
To find this asymptote, we have to look at the range of the function by finding the inverse of the given function. From the given function;
f(x) = \frac{x + 2}{x - 2}
We now write y instead of f(x).
y = \frac{x + 2}{x - 2}
Now, interchange the variables.
x = \frac{y + 2}{y - 2}
Now,make y the subject in order to get the inverse of the function.
x(y - 2) = y + 2
xy - 2x = y + 2
xy - y = 2x + 2
y(x - 1) = 2x + 2
y = \frac{2x + 2}{x - 1}
The range will be x is not equal to 1, since the result will be 0, and,
Therefore, the asymptote will be obtained by looking at the denominator of the inverse of the function; i.e.
x - 1
x = 1
Now, replace x with letter y.
y = 1 \: is \: the \: vertical \: asymptote
Therefore, the asymptotes have been obtained.
I hope you understand the concept.
Thank you;
kaloliavivek
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Please help!!!!<br><br>CE is tangent to this circle, CD is a radius and ECB=48 what is BAC​
den301095 [7]

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