Divide: round to the nearest tenths .48/9.23

What is the answer to the problem i need help with?

AveGali [126]

Answer:

C

Step-by-step explanation:

Recall the equation for a circle:

$(x-h)^2+(y-k)^2=r^2$ , where the center is (h,k) and the radius is r.

The given equation is:

$(x+5)^2+(y+7)^2=21^2$

Another way to write this is:

$(x-(-5))^2+(y-(-7))^2=21^2$

Thus, we can see that h=-5 and k=-7.

The center is at (-5, -7).

6 0

3 years ago

The price of gold is often reported per ounce. At the end of 2005, this price was $513. At the end of 2015, it was $1060. By wha

kondor19780726 [428]

Answer:

106.6 %.

Step-by-step explanation:

That would be (1060- 513) / 513) * 100

= 106.6 %.

7 0

3 years ago

Using the image, determine the length of each arc. m RC= m CBR =

Montano1993 [528]

Given:

Given that the measure of ∠CDR = 85°

We need to determine the measure of $\widehat{RC}$ and $\widehat{CBR}$

Measure of arc RC:

Since, we know that if a central angle is formed by two radii of the circle then the central angle is equal to the intercepted arc.

Thus, we have;

$m\angle CDR = m \widehat{RC}$

Substituting the values, we get;

$85^{\circ} = m \widehat{RC}$

Thus, the measure of $\widehat{RC}$ is 85°

Measure of arc CBR:

We know that 360° forms a full circle and to determine the measure of arc CBR, let us subtract the values 360 and 85.

Thus, we have;

$m\widehat{CBR}=360^{\circ}-m \widehat{RC}$

Substituting the values, we have;

$m\widehat{CBR}=360^{\circ}-85^{\circ}$

$m\widehat{CBR}=275^{\circ}$

Thus, the measure of $\widehat{CBR}$ is 275°

6 0

3 years ago

A movie theater charges $10 for adults and $6 for seniors. On a particular day when 357 people paid in admission, the total rece

olganol [36]

Answer:

Step-by-step explanation:

Determine the types of tickets involved.

There are student tickets and adult tickets.

Create a table to organize the information.

Type

Number

Value ($)

Total Value ($)

Student

6

Adult

9

1

,

506

Step 2. Identify what you are looking for.

We are looking for the number of student and adult tickets.

Step 3. Name. Represent the number of each type of ticket using variables.

We know the number of adult tickets sold was

5

less than three times the number of student tickets sold.

Let

s

be the number of student tickets.

Then

3

s

−

5

is the number of adult tickets.

Multiply the number times the value to get the total value of each type of ticket.

Type

Number

Value ($)

Total Value ($)

Student

s

6

s

Adult

3

s

−

5

9

(

3

s

−

5

)

1

,

506

Step 4. Translate: Write the equation by adding the total values of each type of ticket.

6

s

+

9

(

3

s

−

5

)

=

1506

Step 5. Solve the equation.

6

s

+

27

s

−

45

=

1506

33

s

−

45

=

1506

33

s

=

1551

s

=

47

students

Substitute to find the number of adults.

3

s

−

5

=

number of adults

3

(

47

)

−

5

=

136

adults

Step 6. Check. There were

47

student tickets at

$6

each and

136

adult tickets at

$9

each. Is the total value

$1506

?

We find the total value of each type of ticket by multiplying the number of tickets times its value; we then add to get the total value of all the tickets sold.

47

⋅

6

=

282

136

⋅

9

=

1224

_____

1506

✓

Step 7. Answer the question. They sold

47

student tickets and

136

adult tickets.

5 0

3 years ago

Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon

Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

p | q | p→q

T | T | T

T | F | F

F | T | T

F | F | T

(a) and (b) can be seen from truth tables:

for (a) p∧q:

p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q

T | T | F | F | T | T

T | F | T | T | F | F

F | T | F | T | F | F

F | F | T | T | F | F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

p | q | ¬p | ¬p→q | p∨q

T | T | F | T | T

T | F | F | T | T

F | T | T | T | T

F | F | T | F | F

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0

3 years ago