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3 years ago

How do you solve this equation 6b-2b+8=2+6b

2 answers:

3 0

6b - 2b + 8 = 2 + 6b

6b - 2b = 4b

4b + 8 = 2 + 6b

4b (-4b) + 8 = 2 + 6b (-4b)

8 = 2 + 2b

8 (-2)= 2b + 2 (-2)

6 = 2b

6/2 = 2b/b

b = 3

hope this helps

Stolb23 [73]3 years ago

3 0

6b - 2b + 8 = 2 + 6b......simplify the left side
4b + 8 = 2 + 6b....subtract 2, subtract 4b...from both sides
-2 + 8 = 6b - 4b...simplify
6 = 2b....divide both sides by 2
6/2 = b...simplify
3 = b <=== voila :)

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This can be written as

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$\int {\frac{dy}{e^{y}}} =\int {- 5x dx}$

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Then,

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$ln(e^{-y}) = ln(\frac{5}{2}x^{2} + C)$

Then,

$-y = ln(\frac{5}{2}x^{2} + C)$

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$y = - ln(\frac{5}{2}x^{2} + C)$

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