The second one since the lowest y value is -4 and the values go forever up
<span>
1
4
<
3
4
>
A
1
8
B
3
12
C
1
2
D
6ddddddddddddddddddddd
8</span>
Answer:
3x+y=8 and 3x+y=9
Step-by-step explanation:
Assume these two equations:
a1x+b1y+c1=0
a2x+b2y+c2=0
If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.
In these case, take a look at the last option:

Re-write 'em as a standard form:

So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:

And they do not have any collision point
Some of the many possible answers can be..
3.3
2.2
0.5
Answer:
The school is closest
Step-by-step explanation:
Plot the point of the library and measure the distance from the library to each location.