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3 years ago

15

can somebody please help me with this, also show work so that way i can copy because this is due tmr and i have no clue how to d

o this at all, thank you so much! (also its 8th grade math)

1 answer:

kumpel [21]3 years ago

8 0

27/135 = x/100
27 *100=135*x
2700=135x
Divide both sides by 135
20 =x

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A triangular pyramid with a height of 9 inches has a volume of 63 cubic inches. If the height of the triangular base is 6 inches

Bond [772]

Option D: 21 in is the base length of the triangular base.

Explanation:

Given that a triangular pyramid with a height of 9 inches has a volume of 63 cubic inches.

The height of the triangular base is 6 inches.

We need to determine the base length of the triangular pyramid.

The base length of the triangular pyramid can be determined using the formula,

$Volume =\frac{1}{3} \times Bh$

Substituting $Volume=63$ and $Height=9$ in the above formula, we get,

$63 =\frac{1}{3} \times B(9)$

Simplifying the terms, we get,

$63 =3B$

Dividing both sides by 3, we have,

$21=B$

Thus, the base length of the triangular pyramid is 21 in

Hence, Option D is the correct answer.

3 0

3 years ago

Help could you explain step by step?

mel-nik [20]

Answer:

x = 2 , y = 11

Step-by-step explanation:

the diagonals of a parallelogram bisect each other , then

PT = TR , that is

y = 5x + 1 → (1)

QT = TS , that is

2y = 6x + 10 → (2)

substitute y = 5x + 1 into (2)

2(5x + 1) = 6x + 10

10x + 2 = 6x + 10 ( subtract 6x from both sides )

4x + 2 = 10 ( subtract 2 from both sides )

4x = 8 ( divide both sides by 4 )

x = 2

substitute x = 2 into either of the 2 equations for corresponding value of y

substituting into (1)

y = 5(2) + 1 = 10 + 1 = 11

6 0

2 years ago

Read 2 more answers

Hi can someone please help me on my homework

Murrr4er [49]

Answer:

8. yes, ASA

9. yes, SAS

10. yes, AAS

11. no

12. no

13. yes, SSS

Step-by-step explanation:

4 0

3 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$

= 1 - 18x + 135x² - 540x³ + 1215 $x^{4}$ - 1458 $x^{5}$ + 729 $x^{6}$

----------------------------------------------------------------------------------

Collecting like terms from both expressions

$(1+3x)^{6}$ + $(1-3x)^{6}$

= 2 + 270x² + 2430 $x^{4}$ + 1458 $x^{6}$

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1 5 10 10 5 1

Decreasing powers of 1 from $1^{5}$ to $1^{0}$

Increasing powers of 2x from $(2x)^{0}$ to $(2x)^{5}$

$(1+2x)^{5}$

= 1. $1^{5}$ $(2x)^{0}$ + 5. $1^{4}$ $(2x)^{1}$ + 10. $1^{3}$ $(2x)^{2}$ + 10. $1^{2}$ $(2x)^{3}$ + 5. $1^{1}$ $(2x)^{4}$ + 1. $1^{0}$ $(2x)^{5}$

= 1 + 10x + 40x² + 80x³ + 80 $x^{4}$ + 32 $x^{5}$

8 0

3 years ago

debt A sum of $80000 cam Rs 31000 due in 3 years and a debt of Rs 2000 due in 4 years is to be Paid by single payments 4 years h

Gennadij [26K]

Answer:

551.25

im sorry if its wrong

5 0

3 years ago