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IrinaVladis [17]

3 years ago

6

State the domain of the numbers displayed in column x and column y. x y

1 answer:

ella [17]3 years ago

5 0

We can not really tell in this question as you dont know the equation that is being used for the domain and range relationship but overall one should know that:

The set of values of the independent variable(s) for which a function or relation is defined as the domain of a function. Typically, this is the set of x-values that give rise to real y-values.

The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.

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Each week samantha can pay as much as $15 for her school lunch. Write an inequality showing how much samantha spends on lunch.

Annette [7]

Answer:

$x\leq \$15$

Step-by-step explanation:

Let

x------> amount of money that Samantha spends weekly on her school lunch

we know that

The inequality that represent this situation is

$x\leq \$15$

All positive real number less than or equal to 15

5 0

3 years ago

WILL GIVE 50 POINTS AND BRAINLIEST! <br><br>Write as a square of a binomial: 4.8xy+36y^2+0.16x^2

Bond [772]

Answer:

(6y+0.4x)^2

Step-by-step explanation:

i just did my rsm hw so if ur here from that it's the right answer :)

4 0

2 years ago

Read 2 more answers

Which graph shows a non-proportional linear relationship between x and y?

andreev551 [17]

Answer: B

Because it does not pass through (0,0)

4 0

2 years ago

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Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

as

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

6 0

3 years ago

Given the function: f(x)=x^2+1<br> a) Find f(–6) | b) Find f(8)<br><br> pls help me

ohaa [14]

Answer:

a) f(-6) = 37

b) f(8) = 65

Step-by-step explanation:

f(-6) = (-6)² + 1 = 36 + 1 = 37

f(8) = 8²+ 1 = 64 + 1 = 65

6 0

2 years ago