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vesna_86 [32]
3 years ago
8

Sally can paint a room in 8 hours while it takes steve 7 hours to paint the same room. how long would it take them to paint the

room if they worked together?
Mathematics
1 answer:
77julia77 [94]3 years ago
3 0
Rate for Sally is 1 room per 8hrs
rate for Steve is 1 room per 7hrs

combined rate:
1/8 + 1/7 = 1/T
7/56 + 8/56 = 1/T
15/56 = 1/T
56/15 = T
3 11/15 = 3 hrs 44 min
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Mr. Sarpy went to shoot some hoops on the basketball court. For every shot that he made within the three-point line he earned 2
Lostsunrise [7]

Answer:

x + y = 50 (1) and 2x + 3y = 115 (2); x = 35, y = 15

Step-by-step explanation:

Since x represents the number of 2 point shots and y represents the number of 3 point shots. If the total number of shots is 50, then x + y = 50 (1)

Also, the total 2 point shots is number of 2 point shots × points per shot = 2x and the total 3 point shots is number of 3 point shots × points per shot =  3y. Since the total number of points is 115, then

2x + 3y = 115 (2)

So, the system of equations are

x + y = 50 (1) and 2x + 3y = 115 (2)

We can solve for x and y by substituting x = 50 - y into (2)

So, 2(50 - y) + 3y = 115

100 - 2y + 3y = 115

100 + y = 115

y = 115 - 100

y = 15

So, x = 50 - y

= 50 - 15

= 35

6 0
3 years ago
Laura has $720 and saves $30 a week. Taylor has $1200 and spends $30 a week. in how many weeks will Taylor and Laura have the sa
Setler79 [48]
Let w = number of weeks.

In week w,
Laura has: 720 + 30w
Taylor has: 1200 - 30w

Set the two amounts equal and solve for w, the number of weeks.

720 + 30w = 1200 - 30w

60w = 480

w = 8

They will have the same amount of money in 8 weeks.

Laura will have in 8 weeks:
720 + 30w = 720 + 30 * 8 = 720 + 240 = 960

Taylor will have in 8 weeks:
1200 - 30w = 1200 - 30 * 8 = 1200 - 240 = 960

They will both have $960 in 8 weeks.
4 0
3 years ago
What is the range of the relation below?
Greeley [361]
[6, -infinity)

have a good night
5 0
3 years ago
When a grizzly bear hibernate it’s heart rate drops to 10 beats per minute which 20% of its normal value
sweet [91]

Answer:

true

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
2 years ago
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