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dalvyx [7]
2 years ago
5

see I was genius in my country india website and here no one is answering me when I am in so hurry you know. I am losing marks h

ere. I just came here to seek international knowledge​

Mathematics
2 answers:
Arte-miy333 [17]2 years ago
8 0

Answer:

sorry for that! did you ask a question earlier?

likoan [24]2 years ago
7 0

Answer:

The question you asked should've been easy for a genius...

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Check whether the relation R on the set S = {1, 2, 3} is an equivalent
kozerog [31]

Answer:

R isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let S denote a set of elements. S \times S would denote the set of all ordered pairs of elements of S\!.

For example, with S = \lbrace 1,\, 2,\, 3 \rbrace, (3,\, 2) and (2,\, 3) are both members of S \times S. However, (3,\, 2) \ne (2,\, 3) because the pairs are ordered.

A relation R on S\! is a subset of S \times S. For any two elementsa,\, b \in S, a \sim b if and only if the ordered pair (a,\, b) is in R\!.

 

A relation R on set S is an equivalence relation if it satisfies the following:

  • Reflexivity: for any a \in S, the relation R needs to ensure that a \sim a (that is: (a,\, a) \in R.)
  • Symmetry: for any a,\, b \in S, a \sim b if and only if b \sim a. In other words, either both (a,\, b) and (b,\, a) are in R, or neither is in R\!.
  • Transitivity: for any a,\, b,\, c \in S, if a \sim b and b \sim c, then a \sim c. In other words, if (a,\, b) and (b,\, c) are both in R, then (a,\, c) also needs to be in R\!.

The relation R (on S = \lbrace 1,\, 2,\, 3 \rbrace) in this question is indeed reflexive. (1,\, 1), (2,\, 2), and (3,\, 3) (one pair for each element of S) are all elements of R\!.

R isn't symmetric. (2,\, 3) \in R but (3,\, 2) \not \in R (the pairs in \! R are all ordered.) In other words, 3 isn't equivalent to 2 under R\! even though 2 \sim 3.

Neither is R transitive. (3,\, 1) \in R and (1,\, 2) \in R. However, (3,\, 2) \not \in R. In other words, under relation R\!, 3 \sim 1 and 1 \sim 2 does not imply 3 \sim 2.

3 0
3 years ago
-10p+9p=12 solve this for me please with work shown
ANTONII [103]

-10p +9p =12

combine like terms

p(-10+9) =12

-p =12

divide by -1

p = -12

8 0
3 years ago
Read 2 more answers
In the figure,Line x is parallel to line y. identify the angles congruent to angle 3
san4es73 [151]

Answer:

For example, slide ∠ 1 down the transversal and it will coincide with ∠2. are equal in measure. If two parallel lines are cut by a transversal, the corresponding angles are congruent. If two lines are cut by a transversal and the corresponding angles are congruent, the lines are parallel.

Step-by-step explanation:

8 0
2 years ago
pam uses 1 half cup of milk for each milkshake if she makes 18 milk shakes how many cups of milk does she use
Serga [27]
I am not going to give you the answer, but I am going to tell you how to do it. You first put 18 over 1, and multiply that by one half. (You multiply across.)
5 0
3 years ago
Please help.
Ad libitum [116K]

Answer:  

In what article are you most likely to find the sentence “The coma streamed out until it formed a tail of dust and light”?

“Comets in the Sky”

“How to Punctuate Sentences”

“Water Under the Bridge”

“Medical Histories”

Step-by-step explanation:

8 0
2 years ago
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