Answer:
x>−3
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
84>−24x+12
Step 2: Flip the equation.
−24x+12<84
Step 3: Subtract 12 from both sides.
−24x+12−12<84−12
−24x<72
Step 4: Divide both sides by -24.
−24x
/−24
<
72
/−24
Answer: A'=(1, 3); B'=(-3, 4);C'=(3, 0); D'=(-2, 5)
You can check the PNG attached as well.
Step-by-step explanation:
You need to represent the symmetry of every given points respet to the line
In that case, the line beeing paralell to the x- axis, x- value of the symmetry is the same of the given point and y = 2 is the middle between both points.
Point A(1, 1)
Point B(-3, 0)
Point C(3, 4)
Point D(-2, -1)
Answer:
nope
Step-by-step explanation:
y= 12
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
