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djverab [1.8K]
3 years ago
5

What is the area of the segment?

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0

Answer:

The Area of a Segment is the area of a sector minus the triangular piece (shown in light blue here). There is a lengthy reason, but the result is a slight modification of the Sector formula: Area of Segment = θ − sin(θ) 2 × r2 (when θ is in radians) Area of Segment = ( θ × π 360 − sin(θ)2 ) × r2 (when θ is in degrees)

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The blue dot is at what value on the number line?
Ksenya-84 [330]

Answer:

17.

Step-by-step explanation:

one dash is equal to 2. so just go by twos

4 0
3 years ago
Which expressions are completely factored? Select each correct answer. 32y10−24=8(4y10−3) 18y3−6y=3y(6y2−2) 16y5+12y3=4y3(4y2+3)
laila [671]

Answer:

Option A and Option C

Step-by-step explanation:

Option A: 32y^{10}-24 = 8(4y^{10}-3) This is completely factored as 8 is the Highest Common Monomial factor

Option B: 18y^{3}-6y = 3y(6y^{2}-2) This is not completely factored as 2 is still a common factor of 6y2 and -2.

Option C: 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) This is completely factored as 4y2 is the Highest Common Monomial factor

Option D: 20y^{7}+10y^{2} = 5y(4y^{6}+2y) This is not completely factored as 2y is still a common factor of 4y6 and 2y.

So the options that are completely factored are Option A and Option C

3 0
3 years ago
3x^2+7x+3<br> + 5x^2+12x
Dvinal [7]

Answer:

8x^2+19x

Step-by-step explanation:

Simplify the expression by combining like terms. Terms which look a like and sound a like should be added together.

3x^2+7x+3+5x^2+12x

x^2 terms: 3x^2+5x^2=8x^2

x terms: 7x+12x=19x

constants: 3

Together is is 8x^2+19x+3.

5 0
3 years ago
Read 2 more answers
1. 3,742 x 6= help with step by step
xenn [34]

Answer: The answer is 22,452

Step-by-step explanation: Multiply 6×2 which will be 12

Put the 1 from the 12 on top of the 4 then do 4×6+1 it will equal 25

Then put the 2 on top of the 7 then do 7×6+2 it will equal 44

Then put the 4 on top of the 3 then do 3×6+4 it will equal 22

And that's how you get your answer.

5 0
3 years ago
A uniform bar of length l and weight w is attached to a wall with a hinge that exerts a horizontal force hx and a vertical force
maria [59]
The answer is Hx = ½ Wsin θ cos θ
The explanation for this is:
Analyzing the torques on the bar, with the hinge at the axis of rotation, the formula would be: ∑T = LT – (L/2 sin θ) W = 0
So, T = 1/2 W sin θ. Analyzing the force on the bar, we have: ∑fx = Hx – T cos θ = 0Then put T into the equation, we get:∑T = LT – (L/2 sin θ) W = 0
4 0
4 years ago
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